this post was submitted on 08 Oct 2023
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I'd like to point out that TypeScript is a superset of JavaScript, so if anything goes wrong with it, you can just remove the type information and you'll have regular JavaScript.
I’d still have to do some refactoring in and around my classes though. There’s some syntax that is TypeScript-only, including things like extended classes.
If I take my json and add a .yaml extension it works. If I take my c code and add a .cpp it works. If I take my js code and add a
.ts... it doesn't workTS branches off of the JS syntax (which is great! way better than a syntax rewrite), but TS is not a superset; it does not meet the practical or technical definition of a language superset.
What are the additional requirements? Afaik valid JS is valid TS.
Perfectly valid, and extremely commonly used, coding pattern in JavaScript - it's essentially the normal way to do an associative array or hashmap in JavaScript. It's also one of the commonly used ways to (poorly) simulate OOP in JavaScript.
In TypeScript, it fails. You can't treat an object as an arbitrary key/value pair. That's a good thing... but still, it means TypeScript is not a superset of JavaScript.
AFAIK that source code will be accepted by the TypeScript compiler if the file has a
*.jsextension, but that's an ugly workaround and it also means you can't copy/paste code between files. You have to rewrite the code.No, it doesn't fail. It compiles to perfectly valid JS that runs exactly as you'd expect. The type checking itself errors, because you've made an error - but the compilation isn't prevented by this error.
So yes, Typescript is a superset of JavaScript.
That is an important difference. Still lots of people, myself included, classify "compiler printing an error (not a warning)" as failure, even if bizzarly the code still runs somehow.
That's because you're missing the distinction between compiler and type checker. The compiler doesn't check types, it strips them. The type checker only checks types, it doesn't compile. They are often used in conjunction, though increasingly the compilation is done by e.g. esbuild.
But there is nothing "bizarre" about the code running, since literally, TS is a superset of JS.
Wouldn't it fail in strict mode?
The type checking does, but not the compilation.
Doesn't change the fact that you can strip types and get js
I know a cool library you can use to convert
.tsfiles in Js! It's calledtsc!/s
Type annotations. It can be as simple a adding
anyin front of parameters, but there are other edgecases too, and when you have a really big codebase it can be a pain to convert.Your own example fails because "class" is a valid variable name in c but not cpp.
I didn't say C++ was a superset of C, I said "if I take my c code and add a cpp extension it works". Believe me, I am painfully aware of the not-a-superset problem between C and C++. My point is Typescript doesn't even meet the very loose "its practically a superset" relationship that C++ has with C.
and I pointed out that it doesn't if your C code has a variable called "class".
Don't worry, none of my code uses that, designated initilizers, complex numbers, variable length arrays, typedef name overloading, unintilized constants, implicit void pointer casting, implicit function declarations, nested struct defintions, or any of the other exclusively-C features.