this post was submitted on 01 Nov 2024
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Programming
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Using smart pointers doesn’t eliminate the memory safety issue, it merely addresses one aspect of it. Even with smart pointers, nothing is preventing you from passing references and using them after they’re freed.
To be fair, it's entirely possible to make the same and very similar mistakes in Rust, too.
I'm fairly sure use after free isn't possible unless you explicitly use unsafe code right?
It's compiler enforced is the point.
Yes
Definitively not.
I think you could argue the same point with C++
Neither foo(), nor add_missing_values() looks suspicious. Nonetheless, if
v.push_back(3)
requiresv
to grow, thenref
becomes an invalid reference andstd::cout << ref
becomes UB (use after free). In Rust this would not compiles.It is order of magnitudes easier to have lifetime errors in C++ than in Rust (use after free, double free, data races, use before initialisation, …)
This would be caught by ASan and other tools though, which should be part of any review.
That's why I did not said it was impossible, just order of magnitude harder to catch in C++ compared to Rust.
To have asan finding the bug, you need to have a valid unit test, that has a similar enough workload. Otherwise you may not see the bug with asan if the vector doesn't grow (and thus
ref
would still be valid, not triggering UB), leading to a production-only bug.Asan is a wonderfull tool, but you can't deny it's much harder to use and much less reliable than just running your compiler.
I think you have a hard time understanding the différence between "not possible" and "much harder".
In Rust, the code does not compile.
In C++ the code compile, but
... then the bug will be caught.
Yes it is possible, noone says the opposite. But you can't deny it's harder. And because its harder, more bugs get past review, most notably security bugs as demonstrated again and again in many studies. The