kogasa

It's on purpose. They're trying to avoid calling them people. Not illegal immigrants anymore, just illegals. Not trans people, just things. Yes, the implications of intentional dehumanization are horrific beyond imagination.

Reminded me of a video

https://www.reddit.com/r/PartyParrot/comments/i7o0sn/rude_teddy_bear/

Nice pic

I've felt like this since 2020. I think it just stopped recharging. Is that a thing? Might need to ask about changing my meds.

Thanks

Some of it looks like topology. The curvy horizontal lines turning into curvy vertical lines are symbols relating to the Kauffman bracket, which belongs to knot theory.

https://encyclopediaofmath.org/wiki/Kauffman_bracket_polynomial

I'm with you until the lockin. How does that happen?

Yeah, specifically for something like coreutils I can't see the malicious endgame that is suggested by others here. Is the fear that a proprietary version of cat or pwd or printf takes over the ecosystem and then traps users into a nonfree agreement? Or a proprietary coreutils superset that offers some new tool and does the same thing? Or a proprietary coreutils that generates profit for businesses without attribution to the developers? What would stop anyone from just writing their own proprietary set of tools to do the same thing now, even if uutils didn't exist? Clearly not much, since uutils did exactly that (minus the proprietary bit).

I personally don't see a compelling reason to change to MIT, but I also don't see the problem.

You probably dodged a bullet not playing Cyberpunk on launch. However, you should play it now. Incredible game, really awesome.

It depends on if you use the "relay" feature. If your server is accessible from the outside it shouldn't be using this though.

There's not much coherent algebraic structure left with these "definitions." If Ωx=ΩΩ=Ω then there is no multiplicative identity, hence no such thing as a multiplicative inverse.

Undefined is more precise. 0/0 being an "indeterminate form" refers to expressions of the form lim(x->c) f(x)/g(x) where lim(x->c)f(x) = lim(x->c)g(x) = 0.