It will not "overflow". Signed integer overflow is undefined behavior. The compiler could remove the whole loop or do anything else imaginable (or not).

[–] [email protected] 1 points 1 year ago (1 children)

TIL!

I wonder how many languages out there do define what happens on integer overflow.

[–] BatmanAoD 1 points 1 year ago

Languages with dynamic typing and implicit large-integer types, such as Python and Ruby, generally just convert to that large-integer type.

I figured Java would probably define the behavior in the JVM, but based on a quick web search it sounds like it probably doesn't by default, but does provide library methods to add or subtract safely.

Rust guarantees a panic by default, but provides library methods for wrapping, saturating, and unchecked (i.e. unsafely opting back in to undefined behavior).