this post was submitted on 30 Jul 2024
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How do you "separate" or "explode" a 3D mesh in Godot? (self.godot)
submitted 3 months ago by ICastFist to c/godot
23 comments fedilink hide all child comments
 

I'd like to create an effect similar to 2 death animations that exist in Crash Bandicoot 3.

In one of them, Crash is disintegrated: all the triangle faces get separated and fly apart. A similar triangle separation is seen when he dies from fire, the triangles fall separately.

The second is a simple separation of the legs and torso. One enemy that exists in the 1st stage can cut Crash in half, which will cause the torso to stay in place while the legs walk away.

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[–] [email protected] 2 points 3 months ago (2 children)

I would second CaptDust, exactly what I would do

[–] ICastFist 2 points 3 months ago

What did he say?

[–] [email protected] 1 points 3 months ago* (last edited 3 months ago) (1 children)

It's probably not how naughty dog did it really though 🙂 Andy Gavin is pretty clever, the real Crash disintegration effect is probably individually manipulating the vertices of the character or somethin

[–] ICastFist 1 points 3 months ago (2 children)

I'm guessing Godot doesn't have the means to do something like that, direct manipulation of a mesh's vertices?

[–] [email protected] 2 points 3 months ago (1 children)

Of course it does, you can achieve that with a simple vertex shader by just moving each vertex in the direction of its normal. However, since the vertices are joined into triangles, this will just result in the model getting bigger instead of "disintegrating".

For that to work, you would need a model where each triangle is a separate surface.

Another way which might work would be to enlarge the model like I illustrated above while simultaneously making pixels which are further from an edge than a threshold value transparent.

[–] [email protected] 2 points 3 months ago* (last edited 3 months ago) (2 children)

The vertex shader is low enough level that it has no concept of shared vertices (nor really anything above triangles for the GPU), so this will work without individual meshes.

Here's a quick test project I made using a single cube mesh and the shader code

VERTEX += NORMAL * (sin(TIME)+1.0) *0.1;

[–] [email protected] 2 points 3 months ago

Ah my bad, perfect, then that's the solution!

[–] [email protected] 2 points 3 months ago

Slick!

[–] [email protected] 0 points 3 months ago* (last edited 3 months ago) (1 children)

There's the mesh data tool, but that's not something I've used.

https://docs.godotengine.org/en/stable/classes/class_meshdatatool.html

Also consider something more modern, like shaders. This is older documentation but has pictures. https://docs.godotengine.org/en/3.0/tutorials/3d/vertex_displacement_with_shaders.html

I'll just mention, naughty dog in 96 probably didn't have the luxury of being able to load and swap entire meshes like we do, memory has come a long way so it's probably not necessary to emulate that approach directly. Crash 4 uses a lot of advanced shaders for their challenge levels, very talented work they did there. But if you do anything cool with the tool please post- I'm curious to see end result!

[–] ICastFist 1 points 3 months ago (1 children)

Gamma linked that shader as well, but that doesn't look like the proper tool/shader for exploding/disintegrating the faces

From the looks of it, I'll probably need to copy most of the mesh data into an ArrayMesh and do magic from there

[–] [email protected] 3 points 3 months ago* (last edited 3 months ago)

Usually modern shader displacement attempt to create a continuous mesh, to not have to deal with backfaces or unnatural vertex breaks, but this technique can also be used (funny enough much simpler) to break meshes apart.

Linking a screenshot here I made for another comment in this post, this test project I used the shader code in the vertex shader

VERTEX += NORMAL * (sin(TIME)+1.0) *0.1;

(Should be noted the mesh breaks apart into squares not triangles because the normal of the two triangles in a square is equal)