It doesn't ask you to subtract the numbers, but to calculate the distance (i.e. the absolute value of the subtraction). So depending on which numbers are paired up, the sign of the pair can be different.
Advent Of Code
An unofficial home for the advent of code community on programming.dev!
Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.
AoC 2024
Solution Threads
M | T | W | T | F | S | S |
---|---|---|---|---|---|---|
1 | ||||||
2 | 3 | 4 | 5 | 6 | 7 | 8 |
9 | 10 | 11 | 12 | 13 | 14 | 15 |
16 | 17 | 18 | 19 | 20 | 21 | 22 |
23 | 24 | 25 |
Rules/Guidelines
- Follow the programming.dev instance rules
- Keep all content related to advent of code in some way
- If what youre posting relates to a day, put in brackets the year and then day number in front of the post title (e.g. [2024 Day 10])
- When an event is running, keep solutions in the solution megathread to avoid the community getting spammed with posts
Relevant Communities
Relevant Links
Credits
Icon base by Lorc under CC BY 3.0 with modifications to add a gradient
console.log('Hello World')
True, that is what I did when substracting the sorted lists. I calculated their absolutes.
But I still don't understand why the unsorted method doesn't work. Can you give an example of two lists which this method doesn't work with? Because whatever example I calculated, it was correct.
There's a way to make two length-two lists from 1, 2, 3, 4 that will give you a counter-example.
10 1
2 20
gives 27
But
2 1
10 20
gives 11
You are right. Although the way I was talking about is |(2+10)-(1+20)|= 9 Seems like I coincidentally created some example lists that all worked with this method!
And the algebraic reason would be the presence of parenthesis. |(a+b)-(c+d)| != |(a-c)|+|(b-d)|