this post was submitted on 03 Jul 2023
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How long would this have to run for it to round up to 100%?
A few calculations:
1/ln(x)
. Solving99.9995 = 100 - 100 / ln(x)
for x givese^200000
or7.88 × 10^86858
. In other words, the universe will end before any current computer could check that many numbers.they did the math!