this post was submitted on 04 Feb 2025
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Adding my own explanation, because I think it clicks better for me (especially when I write it down):
p(switch|picked wrong) = 100%)
, so the total chance of the remaining door being correct isp(switch|picked wrong)* p(picked wrong) = 66%
.p(switch|picked right) = 50%
, which means thatp(switch|picked right) * p(picked right) = 50% * 33% = 17%
.p(don't switch|picked wrong) * p(picked wrong) = 50% * 66% = 33%
(because of the remaining doors including the one you picked, you have no more information)p(don't switch|picked right) * p(picked right) = 50% * 33% = 17%
(because both of the unpicked doors are wrong, Monty didn't give you more information)So there's a strong benefit of switching (66% to 33%) if you picked wrong, and even odds of switching if you picked right (17% in both cases).
Please feel free to correct me if I'm wrong here.