Advent Of Code

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Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

AoC 2024

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M	T	W	T	F	S	S
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16	17	18	19	20	21	22
23	24	25

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CameronDev

👻 - 2024 DAY 19 SOLUTIONS -👻 (self.advent_of_code)

submitted 2 weeks ago by CameronDev to c/advent_of_code

34 comments fedilink hide all child comments

Day 19 - Linen Layout

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[–] [email protected] 2 points 2 weeks ago

C

Interestingly part 1 already defied a naive approach. It was fun thinking of a way to memoize without hash tables.

Code

#include "common.h"

static char *pats[480];
static int lens[480];
int np;

/* memoized for 's' by mem[off], 0 = unknown, >0 = value+1 */
static int64_t
recur(char *s, int off, int64_t *mem)
{
	int64_t acc=0;
	int i;

	if (!s[off]) return 1;
	if (mem[off]) return mem[off]-1;

	for (i=0; i<np; i++)
		if (!strncmp(s+off, pats[i], lens[i]))
			acc += recur(s, off+lens[i], mem);

	mem[off] = acc+1;
	return acc;
}

int
main(int argc, char **argv)
{
	static char patbuf[3200], design[64];
	int64_t p1=0,p2=0, mem[64], n;
	char *rest, *lf;

	if (argc > 1)
		DISCARD(freopen(argv[1], "r", stdin));

	rest = fgets(patbuf, sizeof(patbuf), stdin);

	for (; (pats[np] = strsep(&rest, ",")); np++) {
		while (isspace(pats[np][0]))
			pats[np]++;	/* skip spaces */
		if ((lf = strchr(pats[np], '\n')))
			*lf = '\0';	/* trim trailing \n */
		lens[np] = strlen(pats[np]);
		assert(np+1 < (int)LEN(pats));
	}

	while (scanf(" %63s", design) == 1) {
		memset(mem, 0, sizeof(mem));
		n = recur(design, 0, mem);
		p1 += n >0;
		p2 += n;
	}

	printf("19: %"PRId64" %"PRId64"\n", p1, p2);
	return 0;
}

https://codeberg.org/sjmulder/aoc/src/branch/master/2024/c/day19.c

Zee

Also a port to my cursed Dutch dialect of C, Zee:

Code

#ingesloten "zee.kop"
#ingesloten "algemeen.kop"

besloten letterverwijzing patronen[480];
besloten getal lengtes[480];
getal patroonsom;

besloten zeer groot getal
afdaling(
    letterverwijzing tekst,
    getal startpositie,
    zeergrootgetalreeksverwijzing onthouden)
{
	zeer groot getal deelsom=0;
	getal sortering, teller;

	tenzij (tekst[startpositie])
		lever 1;
	mits (onthouden[startpositie])
		lever onthouden[startpositie]-1;

	voor (teller=0; teller < patroonsom; teller++) {
		sortering = tekstdeelvergelijking(
		    tekst + startpositie,
		    patronen[teller],
		    lengtes[teller]);

		mits (sortering == 0) {
			deelsom += afdaling(
			    tekst,
			    startpositie + lengtes[teller],
			    onthouden);
		}
	}

	onthouden[startpositie] = deelsom+1;
	lever deelsom;
}

getal
aanvang(
    getal parametersom,
    letterverwijzingsreeksverwijzing parameters)
{
	blijvende letter patroonruimte[3200];
	blijvende letter ontwerp[64];
	zeer groot getal deel1=0, aantal;
	zeer groot getal deel2=0, onthouden[64];
	letterverwijzing rest;
	letterverwijzing regeleinde;

	mits (parametersom > 1)
		VERWERP(heropen(parameters[1], "r", standaardinvoer));

	rest = geefregel(patroonruimte, grootte(patroonruimte),
	    standaardinvoer);

	voor (; ; patroonsom++) {
		verzeker(patroonsom+1 < (getal)LENGTE(patronen));
		patronen[patroonsom] = tekstsplitsing(naar rest, ",");
		mits (patronen[patroonsom] == NIETS)
			klaar;

		zolang (iswitruimte(patronen[patroonsom][0]))
			patronen[patroonsom]++;
		mits ((regeleinde = zoekletter(patronen[patroonsom], '\n')))
			volg regeleinde = '\0';

		lengtes[patroonsom] = tekstlengte(patronen[patroonsom]);
	}

	zolang (invorm(" %63s", ontwerp) == 1) {
		overschrijf(onthouden, 0, grootte(onthouden));
		aantal = afdaling(ontwerp, 0, onthouden);
		deel1 += aantal >0;
		deel2 += aantal;
	}

	uitvorm("19: %"GEEFZGG" %"GEEFZGG"\n", deel1, deel2);
	lever 0;
}

https://codeberg.org/sjmulder/aoc/src/