this post was submitted on 04 Dec 2024
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Advent Of Code

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An unofficial home for the advent of code community on programming.dev!

Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

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[โ€“] [email protected] 2 points 1 month ago* (last edited 1 month ago)

python

solution

import aoc

def setup():
    return (aoc.get_lines(4, padded=(True, '.', 3)), 0)

def one():
    lines, acc = setup()
    for row, l in enumerate(lines):
        for col, c in enumerate(l):
            if c == 'X':
                w = l[col - 3:col + 1]
                e = l[col:col + 4]
                n = c + lines[row - 1][col] + \
                    lines[row - 2][col] + lines[row - 3][col]
                s = c + lines[row + 1][col] + \
                    lines[row + 2][col] + lines[row + 3][col]
                nw = c + lines[row - 1][col - 1] + \
                    lines[row - 2][col - 2] + lines[row - 3][col - 3]
                ne = c + lines[row - 1][col + 1] + \
                    lines[row - 2][col + 2] + lines[row - 3][col + 3]
                sw = c + lines[row + 1][col - 1] + \
                    lines[row + 2][col - 2] + lines[row + 3][col - 3]
                se = c + lines[row + 1][col + 1] + \
                    lines[row + 2][col + 2] + lines[row + 3][col + 3]
                for word in [w, e, n, s, nw, ne, sw, se]:
                    if word in ['XMAS', 'SAMX']:
                        acc += 1
    print(acc)

def two():
    lines, acc = setup()
    for row, l in enumerate(lines):
        for col, c in enumerate(l):
            if c == 'A':
                l = lines[row - 1][col - 1] + c + lines[row + 1][col + 1]
                r = lines[row + 1][col - 1] + c + lines[row - 1][col + 1]
                if l in ['MAS', 'SAM'] and r in ['MAS', 'SAM']:
                    acc += 1
    print(acc)

one()
two()