this post was submitted on 16 Jun 2024
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Rust

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submitted 4 months ago* (last edited 4 months ago) by [email protected] to c/rust
 

Hey,

Is there any way to create a macro that allows a Some<T> or T as input?

It's for creating a Span struct that I'm using:

struct Span {
    line: usize,
    column: usize,
    file_path: Option<String>,
}

...and I have the following macro:

macro_rules! span {
    ($line:expr, $column:expr) => {
        Span {
            line: $line,
            column: $column
            file_path: None,
        }
    };

    ($line:expr, $column:expr, $file_path: expr) => {
        Span {
            line: $line,
            column: $column
            file_path: Some($file_path.to_string()),
        }
    };
}

...which allows me to do this:

let foo = span!(1, 1);
let bar = span!(1, 1, "file.txt");

However, sometimes I don't want to pass in the file path directly but through a variable that is Option. To do this, I always have to match the variable:

let file_path = Some("file.txt");

let foo = match file_path {
    Some(file_path) => span!(1, 1, file_path),
    None => span!(1, 1),
}

Is there a way which allows me to directly use span!(1, 1, file_path) where file_path could be "file.txt", Some("file.txt") or None?

Thanks in advance!

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[–] v9CYKjLeia10dZpz88iU 1 points 4 months ago* (last edited 4 months ago)

I had commented something similar to stating it was possible to pass the inference problem to the struct if the goal was to support more types, but I removed it because I didn't think my example was easy to understand when reading it later. I made a better example though

https://play.rust-lang.org/?version=stable&mode=debug&edition=2021&gist=8651fa6121840658b4b6249399f693c7