Your code does not follow the pattern matching syntax; I don't see "is" anywhere. That's what is actually doing the casting
Edit: I think I'm completely wrong about "is" being required
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Your code does not follow the pattern matching syntax; I don't see "is" anywhere. That's what is actually doing the casting
Edit: I think I'm completely wrong about "is" being required
I see.
The book uses a very specific scenario where o
is an object that would accept any type. So using the object data type worked. Check the OP for the edit.
An integer will never be a string. Originally you create an integer variable so it's telling you the string case is pointless.
So c# in runtime already knows the type of o(unless you do some silly magic ofcourse) If you wanna change o for debug purposes you can try .GetType() and typeOf
You can check the type with
bool isString = o.GetType() == typeof(string);
(Sorry for any errors I'm on phone so code fiddlers aren't that great)
The book uses a very specific scenario where o
is an object that would accept any type. So using the object data type worked. Check the OP for the edit.