this post was submitted on 03 Dec 2024
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Advent Of Code

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An unofficial home for the advent of code community on programming.dev!

Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

AoC 2024

Solution Threads

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submitted 1 month ago* (last edited 1 month ago) by CameronDev to c/advent_of_code
 

Day 3: Mull It Over

Megathread guidelines

  • Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
  • You can send code in code blocks by using three backticks, the code, and then three backticks or use something such as https://topaz.github.io/paste/ if you prefer sending it through a URL

FAQ

(page 2) 5 comments
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[โ€“] [email protected] 1 points 1 month ago

Elixir

defmodule AdventOfCode.Solution.Year2024.Day03 do
  def part1(input) do
    Regex.scan(~r/mul\((?<l>\d+),(?<r>\d+)\)/, input, capture: ["l", "r"])
    |> Stream.map(fn l -> Enum.reduce(l, 1, &(&2 * String.to_integer(&1))) end)
    |> Enum.sum()
  end

  def part2(input) do
    input |> String.replace(~r/don't\(\).*(do\(\)|$)/Us, "") |> part1
  end
end
[โ€“] [email protected] 1 points 1 month ago

Lisp

Just did some basic regex stuff.

Part 1 and 2


(defun p1-mult (str)
  "pulls out numbers and multiplies them, assumes already filtered by size"
  (let ((vals (ppcre:all-matches-as-strings "\\d+" str)))
    (apply #'* (or (mapcar #'parse-integer vals) '(0)))))

(defun p1-process-line (line)
  "look for mul, do the mul, and sum"
  (let ((ptrn "mul\\(\\d?\\d?\\d,\\d?\\d?\\d\\)"))
    (apply #'+ (mapcar #'p1-mult (ppcre:all-matches-as-strings ptrn line)))))

(defun run-p1 (file) 
  (let ((data (read-file file #'p1-process-line)))
    (apply #'+ data)))

(defun p2-process-line (line)
  "looks for mul, do, and don't"
  (let ((ptrn "(mul\\(\\d?\\d?\\d,\\d?\\d?\\d\\))|(do\\(\\))|(don't\\(\\))"))
    (ppcre:all-matches-as-strings ptrn line)))

(defun p2-filter (data)
  "expects list containing the string tokens (mul, do, don't) from the file"
  (let ((process t))
    (loop for x in data
          when (string= "don't()" x)
            do (setf process nil)
          when (string= "do()" x)
            do (setf process t)
          when process
            sum (p1-mult x))))

(defun run-p2 (file) 
  (let ((data (read-file file #'p2-process-line)))
    ;; treat the input as one line to make processing the do's and don't's easier
    (p2-filter (flatten data))))

[โ€“] Deebster 1 points 1 month ago* (last edited 1 month ago)

Rust feat. pest

No Zalgo here! I wasted a huge amount of time by not noticing that the second part's example input was different - my code worked fine but my test failed ๐Ÿคฆโ€โ™‚๏ธ

pest.rs is lovely, although part two made my PEG a bit ugly.

part1    =  { SOI ~ (mul_expr | junk)+ ~ EOI }
part2    =  { (enabled | disabled)+ ~ EOI }
mul_expr =  { "mul(" ~ number ~ "," ~ number ~ ")" }
number   =  { ASCII_DIGIT{1,3} }
junk     = _{ ASCII }
on       = _{ "do()" }
off      = _{ "don't()" }
enabled  = _{ (SOI | on) ~ (!(off) ~ (mul_expr | junk))+ }
disabled = _{ off ~ (!(on) ~ junk)+ }
use std::fs;

use color_eyre::eyre;
use pest::Parser;
use pest_derive::Parser;

#[derive(Parser)]
#[grammar = "memory.pest"]
pub struct MemoryParser;

fn parse(input: &str, rule: Rule) -> eyre::Result<usize> {
    let sum = MemoryParser::parse(rule, input)?
        .next()
        .expect("input must be ASCII")
        .into_inner()
        .filter(|pair| pair.as_rule() == Rule::mul_expr)
        .map(|pair| {
            pair.into_inner()
                .map(|num| num.as_str().parse::<usize>().unwrap())
                .product::<usize>()
        })
        .sum();
    Ok(sum)
}

fn part1(filepath: &str) -> eyre::Result<usize> {
    let input = fs::read_to_string(filepath)?;
    parse(&input, Rule::part1)
}

fn part2(filepath: &str) -> eyre::Result<usize> {
    let input = fs::read_to_string(filepath)?;
    parse(&input, Rule::part2)
}

fn main() -> eyre::Result<()> {
    color_eyre::install()?;

    let part1 = part1("d03/input.txt")?;
    let part2 = part2("d03/input.txt")?;
    println!("Part 1: {part1}\nPart 2: {part2}");
    Ok(())
}
[โ€“] [email protected] 1 points 1 month ago

TypeScript

Solution

import { AdventOfCodeSolutionFunction } from "./solutions";

export const solution_3: AdventOfCodeSolutionFunction = (input) => {
    const mul_regex = /mul\((\d+),(\d+)\)/g; // mul()
    const do_regex = /do\(\)/g;              // do()
    const do_not_regex = /don\'t\(\)/g;      // don't()

    const doLength = "do()".length;
    const doNotLength = "don't()".length;

    let input_copy = "" + input;
    let part_1 = 0;
    let part_2 = 0;
    let isEnabled = true;
    while (true) {
        const nextMul = input_copy.search(mul_regex);
        const nextDo = input_copy.search(do_regex);
        const nextDoNot = input_copy.search(do_not_regex);
        let pointer = Number.POSITIVE_INFINITY;

        // find the smallest while ignoring items that are not found
        if (nextMul != -1)
            pointer = Math.min(pointer, nextMul);

        if (nextDo != -1)
            pointer = Math.min(pointer, nextDo);

        if (nextDoNot != -1)
            pointer = Math.min(pointer, nextDoNot);

        // no matches
        if (pointer == Number.POSITIVE_INFINITY)
            break

        // handle found command
        switch (pointer) {
            case nextDo: {
                pointer += doLength;
                isEnabled = true;
                break;
            }

            case nextDoNot: {
                pointer += doNotLength;
                isEnabled = false;
                break;
            }

            case nextMul: {
                const res = input_copy.matchAll(mul_regex).next().value;
                if (!res) {
                    // this should never happen but here's an escape hatch
                    throw Error("regex result is undefined or null");
                }

                // add the length of the whole capture to the pointer
                pointer += res[0].length;
                
                // multiply capture groups
                const comp = Number(res[1]) * Number(res[2]);

                // part 1 sum
                part_1 += comp;

                // part 2 sum
                if(isEnabled)
                    part_2 += comp;

                break;
            }
        }

        // shorten the start of the string
        input_copy = input_copy.slice(pointer);
    }

    return {
        part_1,
        part_2,
    };
}

This one was harder but still. I feel like I can improve it for sure :)

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