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Nice (lemmy.fmhy.ml)

submitted 1 year ago by [email protected] to c/[email protected]

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[–] [email protected] 41 points 1 year ago* (last edited 1 year ago) (1 children)

Huh, that's true of any number that ends in 9.

XY + X + Y = 10*X + Y

Y's cancel,

XY = 9X => Y = 9 for any non-zero finite value of X.

so for 69? X = 6, Y=9

(6*9) + 6 + 9 = 10*6 + 9

54 + 15 = 69

69 = 69 (nice!)

429? X = 42 Y = 9

(42*9) + 42 + 9 =10*42 + 9

(378) + 51 = 429

429 = 429

Even if 10X+Y doesn't equal something that ends in 9 it works

X=3.14 Y=9

(3.14*9) + 3.14 + 9 = 10*3.14 + 9

28.26 + 12.14 = 40.4

40.4 = 40.4

Doesn't work if Y =\= 9:

68? X = 6 Y = 8

(6*8) + 6 + 8 ?= 10*6 + 8

(48) + 14 ?= 68

62 =\= 68

[–] [email protected] 5 points 1 year ago (1 children)

I wanted to try to properly prove that it didn't work for y!=9, but I think you covered the edge cases - X=0 or unbounded. Well done!

[–] [email protected] 3 points 1 year ago* (last edited 1 year ago)

I'm an engineering major, we learn all of the edge cases as "well technically this isn't always true, but we'll just pretend it is because the results are close enough"

Every value of Y works for X=0, the equation simplifies to Y=Y, so X=0 is just like Y=9.

In the limit as X->infinity, you get Y = 9 again.

X(1+Y) + Y = 10*X + Y lim X->inf Assuming Y is finite, you drop the non-X terms

X(1+Y) = 10*X lim x->inf

Here, because X is non-zero and equal to itself, you can cancel them (I assume, IANA Mathematician) 1 + Y = 10 Y = 9