this post was submitted on 28 Aug 2023
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Pathfinder 2e General Discussion

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A level 5 rogue will quite probably have a thievery dc of 13, if they invest in it and max dex. The average lock has a dc of 25 and requires 4 successes. It takes a roll of 12 or better to have a single success, and will average about 9 rolls to rack up those 4 successes. With 9 rolls wherein you crit fail on a 2 or lower, the likelihood of breaking a pick is ~61%.

Should a level 5 rogue take a minute to open the average lock, and more likely than not break a pick in the process?

And let's look at a good Lock: DC 30, requiring 5 successes. The level 5 rogue will only succeed on a 17, meaning it will take on average 20 attempts to get those 5 successes. On one attempt in a thousand our Lvl 5 rogue will open this lock before breaking a pick, and will typically break 3 in the process.

Am I missing something?

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[–] [email protected] 3 points 1 year ago (1 children)

My other issue is that from a gameplay perspective, if there is no ongoing fight and we are not in encounter mode, I don’t see at all the point to make so many rolls and require several successes.

Isn't that why old editions of D&D let you take 20 on a lot of out-of-combat things? I'm still not sure why that was removed from both D&D and Pathfinder.

[–] [email protected] 2 points 1 year ago

Exactly. Take 20 when there is no consequence of failure and plenty of time. Take 10 when there is plenty of time and no stresfull environment.