this post was submitted on 03 May 2025
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[โ€“] [email protected] 4 points 1 week ago (1 children)

Ok, assume you pick door number one. There's three possibilities; the car is either behind door number one, two or three. Now:

  1. First scenario, the car is behind door number one. Monty opens door two or three, you switch doors and don't win a car.
  2. Second scenario, the car is behind door number two. Monty opens door three, you switch doors to number two and win a car.
  3. Third scenario, the car is behind door number three. Monty opens door two, you switch doors to number three and win a car.

So two out of three times, you've won a car by switching doors. So you have a 2/3 chance of winnin by switching, or a 1/3 chance by not switching.

[โ€“] [email protected] 2 points 1 week ago

Very good explanation, thanks!

I didn't provide the exact numbers, but stated that because the odds are now better for a random selection, is the reason for switching. Am I that bad at explaining ๐Ÿ˜ญ