this post was submitted on 29 Nov 2024
310 points (96.1% liked)

Science Memes

11486 readers
1277 users here now

Welcome to c/science_memes @ Mander.xyz!

A place for majestic STEMLORD peacocking, as well as memes about the realities of working in a lab.

Rules

  1. Don't throw mud. Behave like an intellectual and remember the human.
  2. Keep it rooted (on topic).
  3. No spam.
  4. Infographics welcome, get schooled.

This is a science community. We use the Dawkins definition of meme.

Research Committee

Other Mander Communities

Science and Research

Biology and Life Sciences

Physical Sciences

Humanities and Social Sciences

Practical and Applied Sciences

Memes

Miscellaneous

founded 2 years ago
MODERATORS
[email protected]
[email protected]
[email protected]
310
Fuck geometry (lemm.ee)
submitted 1 month ago by [email protected] to c/[email protected]
48 comments fedilink hide all child comments
 
you are viewing a single comment's thread
view the rest of the comments
[–] [email protected] 86 points 1 month ago (5 children)

This triangle is impossible.

If the distance between B and C is 0, B and C are the same points. If that is the case, the distances between A and B and A and C must be the same.

However, i ≠ 1.

If you want it to be real (hehe) the triangle should be like this:

    C
    | \
|i| |  \ 0
    |   \
    A---B
     |1|

Drawing that on mobile was a pain.

As the other guy said, you cannot have imaginary distances.

Also, you can only use Pythagoras with triangles that have a 90° angle. Nothing in the meme says that there's a 90° angle. As I see it, there are only 0° and 180° angles.

Goodbye, I have to attend other memes to ruin.

[–] [email protected] 21 points 1 month ago (1 children)

Context matters. In geometry i is a perfectly cromulent name for a real valued variable.

[–] [email protected] 4 points 1 month ago (1 children)

Oh shit, he used the word cromulent. Every one copy off this guy.

[–] [email protected] 2 points 1 month ago

That wouldn't be cromulent, would it?

[–] [email protected] 12 points 1 month ago

Mad mobile drawing!!

[–] [email protected] 5 points 1 month ago* (last edited 1 month ago) (1 children)

As the other guy said, you cannot have imaginary distances.

Incorrect. There are complex valued metric spaces

And even if we assume real valued metrics, then i usually represents the unit vector (0,1) which has distance real 1.

[–] [email protected] 1 points 1 month ago (1 children)

That's NOT a metric. That's a measure. Two wholly different things.

[–] [email protected] 3 points 1 month ago (1 children)

It can be a pseudometric

[–] [email protected] 1 points 1 month ago

That's more related to a metric but it still can't be complex valued and it's still not a measure.

[–] [email protected] 1 points 1 month ago (1 children)

This is clearly meant to be a right triangle. And the distances between the points are the same (because the squares of the coordinate differences are the same), just the directions are different.

If you move 1 unit forward, turn the correct 90 degrees, and then move i units forward, you will end up back where you started.

[–] [email protected] 1 points 1 month ago (1 children)

You can't have a distance in a "different direction". That's what the |x| is for, which is the modulus. If you rotate a triangle, the length of the sides don't change.

[–] [email protected] 1 points 1 month ago

The vector from one point to another in space has both a distance (magnitude) and a direction. Labeling the side with i only really makes sense if you say we're looking at a vector of "i units that way", and not at an assertion that these two points are a directionless i units apart. Then you'd have to break out the complex norms somebody mentioned.

[–] [email protected] -1 points 1 month ago (1 children)

Isnt it fine to assume a 90° angle its just that when u square side AC ur multiplying by i which also represents a rotation by 90° so u now nolonger have a triangle?

[–] [email protected] 3 points 1 month ago (1 children)

It's not fine to assume a 90° angle. The distance between B and C is 0. Therefore the angle formed by AB and AC is 0°.

If the angle is 90°, then BC should be sqrt(2), not 0. Since the length of both sides is 1. sqrt(|i|^2+|1|^2) = sqrt(2).

[–] [email protected] 0 points 1 month ago

So essentially what ur saying is. The imaginary and real arent 90° or pythagoras is only valid for real numbers?