this post was submitted on 26 Aug 2023
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I'm updating foundry to a version 11 and it broke an ass ton of my assets cause they're all "verified version 10"

So all I have to do is change that number, they're just maps so no need to update anything else, but I have like 400+ files to convert all in individual folders.

Please tell me there's an easy way to do this. (I'm on Linux obviously)

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[–] [email protected] 32 points 1 year ago* (last edited 1 year ago) (2 children)
for file in $(find . -type f -iname '*.json'); do
  sed -i 's/"verified":"10"/"verified":"11"/' $file;
done
[–] [email protected] 26 points 1 year ago (2 children)

Find can actually do the sed itself if you don't want to use a subshell and a shell loop.

find . -type f -iname '*.json' -exec sed -i 's/"verified":"10"/"verified":"11"/' '{}' ';'
[–] [email protected] 8 points 1 year ago (1 children)

-print0 | xargs -0 sed -i to get a single sed process working across multiple files.

Add a -P 8 to xargs to get 8 parallel processes.

[–] [email protected] 4 points 1 year ago

Today I learned that xargs supports parallelization natively! That's gonna make some of my scripts much simpler

[–] [email protected] 7 points 1 year ago

Change the ';' to a '+' for even more efficiency (no need to fork+exec a sed process per file, sed can take multiple files)

[–] [email protected] 8 points 1 year ago

+1

And

In the off chance the files are not under git or some other VCS, might be a good idea to add the -b option to backup

[–] [email protected] 26 points 1 year ago (2 children)

With sed or awk, without a sample is hard to give a proper example.

sed -i 's/old/new/g' *.json 
[–] [email protected] 15 points 1 year ago

That rhymes!

With sed or awk, without a sample
is hard to give, a proper example

[–] [email protected] 5 points 1 year ago* (last edited 1 year ago)

Name checks out, this is the way

Our sedvior!

[–] [email protected] 12 points 1 year ago* (last edited 1 year ago)

You could use jq, which will work no matter how the json is formatted.

Without trying it out, something like the following might work:

jq '.path.to.key.to.change |= 11' file.json > file.json.tmp && mv file.json.tmp file.json

[–] [email protected] 11 points 1 year ago (2 children)

I also agree sed and some regex is your best bet

I recommend formatting the regex with regex101.com, I'm down to help you if you post some examples

Additionally there is a cli tool, I think jq or something like that, for processing json on the command line

I have foundry too, let me see if I can find the files that need to be updated

[–] [email protected] 2 points 1 year ago* (last edited 1 year ago) (1 children)

Here's the GitHub link to one of the batches of files I'm working with.

This line ,,"compatibility":{"minimum":"9","verified":"10"}," needs to say" 11" in all the files

[–] [email protected] 5 points 1 year ago* (last edited 1 year ago) (4 children)

I have made a python script and ran it on a clone of your git repo to confirm it works, simply run it at the root directory of wherever the files are, it will walk through and find module.json and do the replace.

#!/usr/bin/env python3

import re
import os

import fileinput

pattern = re.compile(r'(?P\.+)\"compatibility\":{\"minimum\":\"(?P\\d+)\",\"verified\":\"(?P\\d+)\"},(?P\.+)')

def make11(match):
    if match.groupdict().get('min', None) and match.groupdict().get('ver', None):
        return f"{match.groupdict()['pre']}\"compatibility\":{{\"minimum\":\"11\",\"verified\":\"11\"}},{match.groupdict()['post']}"

for root, dirs, files in os.walk("."):
    for file in files:
        if file == "module.json":
            for line in fileinput.input(f"{root}/{file}", inplace=True):
                print(re.sub(pattern, make11, line))

edit: lemmy is fucking with the formatting and removing the fucking regex group names, which will bork it. I've tried fixing it, dm me if you want me to send a downloadable link to the script

[–] [email protected] 6 points 1 year ago

Neat script; just a touch overkill IMO compared to just using sed and bash!

Changing the minimum may be undesirable - I think it's only the latter value that needs to go from 10 -> 11.

[–] [email protected] 6 points 1 year ago

If using Python, why not just use JSON module? Simpler and easier maintain without all those regex.

Still +1, on sed if one is on Linux.

[–] [email protected] 1 points 1 year ago

Holy shit that's awesome! Thanks

[–] [email protected] 1 points 1 year ago* (last edited 1 year ago)

I also agree sed and some regex is your best bet

Nah, regexes are okay if you really have no other choice, but they're a bit of a hamfisted tool. For a json file, which is a neatly structured format, I would always try to do it with jq first.

[–] [email protected] 8 points 1 year ago

sed or awk might get you there, but something like jq which is meant for json might be a bit more ideal depending on your use-case.

[–] [email protected] 5 points 1 year ago (1 children)

find /path -name *.json -exec sed -i 's/from/to/g' {} ; -print

[–] [email protected] 2 points 1 year ago* (last edited 1 year ago) (1 children)

This, unless you want to mess with jq

[–] [email protected] 0 points 1 year ago (2 children)

Yeah, jq doesn't edit files, right? You'd have to have temp files or something? jq is so good handling json, I wish there was a way of using it to edit files.

[–] [email protected] 3 points 1 year ago

You really want to do it that way anyway.. process the files to a new set of files. That way when you screw it up going back is just deleting the new files, fixing and rerunning.

[–] [email protected] 1 points 1 year ago (1 children)

Output redirect back into the file

[–] [email protected] 3 points 1 year ago (2 children)

That'll give you an empty file 🙂

[–] [email protected] 1 points 1 year ago

Oh yea, you’re right

[–] [email protected] 1 points 1 year ago

Typical rookie mistake :D

[–] [email protected] 4 points 1 year ago* (last edited 1 year ago) (1 children)

Since I don't know the structure of your files, I can't help entirely, but I would use find/locate to get a list of file paths, then use a script to take that list and use sed for the replacement, like this:

#!/bin/bash
for i in ListOfFilePaths.txt
do
  sed -i "s/oldtext/newtext/g" $i
done

Please copy the entire line for oldtext and newtext to avoid accidental replacements.

Also, I am very new to scripting, and this likely has multiple problems with it. I am just throwing out ideas.

[–] [email protected] 4 points 1 year ago* (last edited 1 year ago) (1 children)

Looked at your github. I would do this in a script:

#!/bin/bash
find /base/path/of/files -type f -name "module.json" > ListOfFilePaths.txt

for i in ListOfFilePaths.txt
do
  sed -i "s/oldtext/newtext/g" $i
done

Once again, probably not the most efficient way to do it, but it might work.

[–] [email protected] 3 points 1 year ago

Thanks I'll give that a try!

[–] [email protected] -3 points 1 year ago* (last edited 1 year ago) (1 children)

Not sure but you can always ask chatgpt. Probably using something like sed or awk

[–] [email protected] 3 points 1 year ago (1 children)

I would love to see what it spit out if you feed it exactly what OP asked.

[–] [email protected] 1 points 1 year ago (1 children)

This was the response from chatgpt when I coppied OP's exact post. It wasn't too far off:

Yes, there's a way to automate this process using a script. You can use a combination of the find command and sed to search and replace the version number in all your files. Here's a sample command you can use:

find /path/to/assets -type f -name "*.asset" -exec sed -i 's/verified version 10/verified version 11/g' {} +

Replace /path/to/assets with the actual path to your asset folders. This command will recursively search for .asset files and replace "verified version 10" with "verified version 11". Make sure to have a backup of your files before running this command, just in case.

Also, consider testing this on a smaller set of files first to ensure it works as expected before applying it to all 400+ files.

[–] [email protected] 2 points 1 year ago

Cool. Thanks for posting that.