this post was submitted on 28 Aug 2024
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Differential calculus? That looks more like algebra. Their speed is constant.
Each of their speeds is constant, but different, and they're walking in different directions.
Their distance is the hypotenuse of a triangle with sides 5t and t which will be root((5t)^2^ + t^2^). So the distance at time t of the ex lovers will be root(26) × t. You can basically grasp intuitively that the speed is indeed constant and equals to the root(26)=5.1 ft/sec. Technically you’d use the derivative power rule to drop the t and get the speed.